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N으로 표현

Question

Test Case 1

def solution(N, number): possible_number = [[], [N]] if number == N: return 1 for count in range(2, 9): temp = set([int(str(N) * count)]) for j in range(1, count // 2 + 1): for num1 in possible_number[j]: for num2 in possible_number[count - j]: temp.update(calculate(num1, num2)) if number in temp: return count possible_number.append(list(temp)) return -1 def calculate(num1, num2): result = set() result.add(num1 + num2) result.add(num1 - num2) result.add(num2 - num1) result.add(num1 * num2) if num1 != 0: result.add(num2 / num1) if num2 != 0: result.add(num1 / num2) return result
Shell
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Test Case 2

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Solve

Python
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실행시간 : ms